Law of Chemical Equilibrium and Equilibrium Constants

IMPORTANT

Law of Chemical Equilibrium and Equilibrium Constants: Overview

This topic covers concepts such as Law of Mass Action, Forward Rate Constant, Backward Rate Constant, Equilibrium Constant, Significance of Equilibrium Constant, Characteristics of Equilibrium Constant, Calculating Equilibrium Constant, etc.

Important Questions on Law of Chemical Equilibrium and Equilibrium Constants

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IMPORTANT

At constant temperature, the equilibrium constant  (Kp) for the decomposition reaction  N2O4(g)2NO2(g)  is expressed by Kp=4x21-x2P , where P = pressure, x = extent of decomposition. Which one of the following statements is true?

MEDIUM
IMPORTANT

At constant temperature, the equilibrium constant   ( K p ) for the decomposition reaction  N2O4(g)2NO2(g)  is expressed by kp=(4x2P)(1-x2) , where P = pressure, x = extent of decomposition. Which one of the following statements is true?

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When two reactants, A and B are mixed to give products C and D, the reaction quotient Q, at the initial stage of the reaction :–

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IMPORTANT

For the reversible reaction,  N2(g)+3H2g2NH3(g) at 500°C, the value of  Kp is   1.44× 10 5 when partial pressure is measured in the atmosphere. The corresponding value of  Kc, with concentration in mol L-1, is: 

MEDIUM
IMPORTANT

For the reversible reaction N2(g)+3H2(g)2NH3(g) at 500°C , the value of Kp is  1.44× 10 5 when partial pressure is measured in atmosphere. The corresponding value of Kc, with concentration in mol litre-1, is:

MEDIUM
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The Haber’s process for the formation of   NH 3 at 298 K is

 N2+3H22NH3;ΔH=46.0J.

Which of the following is the correct statement –

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When two reactants A and B are mixed to give products C and D, the reaction quotient Q at the initial stage of the reaction is best described by-

MEDIUM
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For the reversible reaction, N2(g)+3H2(g)2NH3(g) at 500°C , the value of Kp is 1.44× 10 5 , when partial pressure is measured in the atmosphere. The corresponding value of Kc, with the concentration in mole litre-1, is

MEDIUM
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For the chemical reaction   3X( g )+Y(g) X 3 Y( g ) , the amount of   X 3 Y at equilibrium is affected by –

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What is the equilibrium expression for the reaction,   P 4 (s) + 5O 2 (g)   P 4 O 10 (s) ?

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For the reaction equilibrium,   N 2 O 4 (g)   2NO 2 (g) the concentrations of   N 2 O 4 and   NO 2 at equilibrium are   4.8×1 0 -2 and1.2×1 0 -2 mol L -1 respectively. The value of Kc for the reaction is –

EASY
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The equilibrium constant for the reaction H2Ol+COgH2g+CO2g is 64. If the rate constant for the forward reaction is 160, the rate constant for the backward reaction is 

HARD
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COF2 gas passed over a catalyst at 1000 °C comes to equilibrium:

2COF2 (g)CO2 (g)+CF4 (g)

Analysis of the equilibrium mixture (after quick cooling to freeze the equilibrium) shows that 500 mL of the equilibrium mixture (NTP) contains 300 mL (NTP) of COF2 and CO2. Taking the total pressure to be 10 atm, calculate Kp.

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What are the factors that affect the forward rate constant?

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What is the forward rate constant?

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The rate of a reaction is inversely proportional to the product of the concentrations of the reactants each raised to the power of their stoichiometric coefficient.

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How will you relate forward rate of a reaction with a forward rate constant based on law of mass action?

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 An expression for the backward rate constant of the reaction, aA+bB            cC+dD is

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In an equilibrium reaction, the rate constant for the forward reaction is 1.125×10-3. Calculate the rate constant for the backward reaction if the equilibrium constant is 1.5.

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IMPORTANT

Write an expression for the backward rate constant of the reaction, 2NO2g             N2g+2O2g.